An object with a mass of $2 k g$ $2 kg$ is lying still on a surface and is compressing a horizontal spring by $70 c m$ $70 c m$ . If the spring's constant is $9 \frac{k g}{s^{2}}$ $9 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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Answer 1 · 2017-04-25T17:01:22

The coefficient of ctatic friction is $= 0.32$ $=0.32$

The force of friction is

$F_r=k*Deltax$

The spring constant is $k=9kgs^-2$

The distance is $Deltax=0.7m$

Therefore,

$F_r=9*0.7=6.3N$

The coefficient of static friction is

$mu_s=F_r/N$

The normal force is $N=mg=(2g) N$

So,

$mu_s=(6.3)/(2g)=0.32$

An object with a mass of 2 kg2kg 2 kg is lying still on a surface and is compressing a horizontal spring by 70 c m70cm70 c m. If the spring's constant is 9 (kg)/s^29kgs2 9 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?