An object with a mass of $2 k g$ $2 kg$ is lying still on a surface and is compressing a horizontal spring by $70 c m$ $70 c m$ . If the spring's constant is $3 \frac{k g}{s^{2}}$ $3 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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Answer 1 · 2017-04-23T09:40:57

The coefficient of static friction is $= 0.11$ $=0.11$

The force of friction is

$F_r=k*Deltax$

The spring constant is $k=3kgs^-2$

The distance is $Deltax=0.70m$

Therefore,

$F_r=3*0.70=2.1N$

The coefficient of static friction is

$mu_k=F_r/N$

The normal force is $N=mg=(2g) N$

So,

$mu_k=2.1/(2g)=0.11$

An object with a mass of 2 kg2kg 2 kg is lying still on a surface and is compressing a horizontal spring by 70 c m70cm70 c m. If the spring's constant is 3 (kg)/s^23kgs2 3 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?