An object with a mass of $2 kg$ is on a surface with a kinetic friction coefficient of $7$ . How much force is necessary to accelerate the object horizontally at $6 m/s^2$ ?

Question

An object with a mass of $2 kg$ is on a surface with a kinetic friction coefficient of $7$ . How much force is necessary to accelerate the object horizontally at $6 m/s^2$ ?

1 Answer

Impact of this question

1544 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-12-20T23:48:24

I found: $F=149.2N$

Explanation:

Kinetic Friction is given as:
$f_k=mu_k*N$
Where:
$mu_k=$ kinetic friction coefficient $=7$
$N=$ Normal Reaction (in this case of horizontal movement) $="weight"=mg$
with:
$m=2kg$
$g=9.8m/s^2$

To produce an acceleration $a=6m/s^2$ we need a force $F$ to overcome friction that, according to Newton's Second Law, will be given as:
$F-f_k=ma$
$F=f_k+ma$
$F=mu_k*mg+ma$
$F=(7*2*9.8)+(2*6)=149.2N$

Science

Math

Humanities

... and beyond

An object with a mass of $2 kg$ is on a surface with a kinetic friction coefficient of $7$ . How much force is necessary to accelerate the object horizontally at $6 m/s^2$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

An object with a mass of 2 kg2 kg is on a surface with a kinetic friction coefficient of 7 7 . How much force is necessary to accelerate the object horizontally at 6 m/s^26 m/s^2?

1 Answer

Explanation:

Related questions

Impact of this question

An object with a mass of $2 kg$ is on a surface with a kinetic friction coefficient of $7$ . How much force is necessary to accelerate the object horizontally at $6 m/s^2$ ?