An object with a mass of $2 k g$ $2 kg$ is on a surface with a kinetic friction coefficient of $3$ $3$ . How much force is necessary to accelerate the object horizontally at $6 \frac{m}{s^{2}}$ $6 m/s^2$ ?

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An object with a mass of $2 k g$ $2 kg$ is on a surface with a kinetic friction coefficient of $3$ $3$ . How much force is necessary to accelerate the object horizontally at $6 \frac{m}{s^{2}}$ $6 m/s^2$ ?

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Answer 1 · 2018-03-04T10:56:31

$70.8 N$ $70.8 N$

Explanation:

Here,if we have to move the object against frictional force with acceleration,then frictional force must be exerting its maximum value against the motion.

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Maximum frictional $f$ $f$ force that can act here is $μ N = μ g = 3 \cdot 2 g = 6 \cdot 9.8 = 58.8 N$ $muN=mug=3*2g=6*9.8=58.8N$ (where, $μ$ $mu$ is the coefficient of kinetic friction)

So,if we need to apply force $F$ $F$ to accelerate it at an acceleration of $a$ $a$ ,

Then we can write,acceleartion which is due to the net force acting is,

$F - f = m a$ $F-f=ma$

or, $F - 58.8 = 2 \cdot 6$ $F-58.8=2*6$

so, $F = 70.8 N$ $F=70.8 N$

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An object with a mass of $2 k g$ $2 kg$ is on a surface with a kinetic friction coefficient of $3$ $3$ . How much force is necessary to accelerate the object horizontally at $6 \frac{m}{s^{2}}$ $6 m/s^2$ ?

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An object with a mass of 2kg2 kg is on a surface with a kinetic friction coefficient of 3 3 . How much force is necessary to accelerate the object horizontally at 6ms26 m/s^2?

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An object with a mass of $2 k g$ $2 kg$ is on a surface with a kinetic friction coefficient of $3$ $3$ . How much force is necessary to accelerate the object horizontally at $6 \frac{m}{s^{2}}$ $6 m/s^2$ ?