An object with a mass of 2kg is on a surface with a kinetic friction coefficient of 9. How much force is necessary to accelerate the object horizontally at 3ms2?

1 Answer
Feb 3, 2016

There are two components of the required force: one to overcome the frictional force and one to accelerate the object. The total force is F=ma+μmg=23+929.8=6+176.4=182.4N

Explanation:

To accelerate a mass on a frictionless surface, it is just necessary to apply the force described by Newton's Second Law:

F=ma

In this case, an additional force is required to overcome the frictional force, which is defined this way:

Ffrict=μFnorm where μ is the frictional coefficient and Fnorm is the normal force.

The normal force in this case is just the weight force of the object:

Fnorm=mg

Pulling it all together to find the total force, we get:

F=ma+Ffrict=ma+μFnorm=ma+μmg

Substituting in the values from the question:

F=ma+μmg=23+929.8=6+176.4=182.4N

(I remarked on another similar question, but it bears repeating here: 9 is not a reasonable or sensible value for a coefficient of friction. The fault is with the teacher or book asking the question in the first place, not the student asking it here. Friction coefficients are typically between 0 and 1, sometimes slightly above 1, in some extreme cases approaching 2, but 9 is just way off the scale. 0.9 would be a much more sensible number.)