An object with a mass of $2 k g$ $2 kg$ is on a surface with a kinetic friction coefficient of $2$ $2$ . How much force is necessary to accelerate the object horizontally at $8 \frac{m}{s^{2}}$ $8 m/s^2$ ?

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Answer 1 · 2018-04-23T09:34:19

$55.2 N$ $"55.2 N"$

From Newton’s second law on a smooth surface

$F = ma$ $"F = ma"$

But here surface is not smooth. Extra force is required to neutralise the effect of friction

$F = ma + μmg$ $"F = ma + μmg"$

$F = ({2 kg \times 8 m/s}^{2}) + ({2 \times 2 kg \times 9.8 m/s}^{2})$ $"F" = ("2 kg × 8 m/s"^2) + ("2 × 2 kg × 9.8 m/s"^2)$

$F = 16 N + 39.2 N = 55.2 N$ $"F = 16 N + 39.2 N = 55.2 N"$

An object with a mass of 2kg2 kg is on a surface with a kinetic friction coefficient of 2 2 . How much force is necessary to accelerate the object horizontally at 8ms28 m/s^2?