Question

An object with a mass of `2 kg` is revolving around a point at a distance of `5 m`. If the object is revolving at a rate of `3 Hz`, what is the centripetal force on the object?

Answer 1

`F_c = 3.6N`

Explanation:

The formula for centripetal force is,
`F_c = mv^2 /r`

`m = 2k_g`
`v = 3ms^-1`, because `1H_z = 1sec`
`r = 5m`

`= 2 3^2/5`

`= 3.6N`