An object with a mass of $2 k g$ $2 kg$ is revolving around a point at a distance of $5 m$ $5 m$ . If the object is revolving at a rate of $5 H z$ $5 Hz$ , what is the centripetal force on the object?

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Answer 1 · 2017-05-05T12:52:43

I got $9860 N$ $9860N$

The rate of $5 H z$ $5Hz$ means that the object makes $5$ $5$ revolutions in one second.

This means that it will travel a total linear distance of $d = 5 \cdot 2 π r$ $d=5*2pir$ (five times the circumference) during one second, or:

$d = 10 \cdot π \cdot 5 = 157 m$ $d=10*pi*5=157m$

so, also its velocity will be: $\frac{d}{t} = \frac{157}{1} = 157 \frac{m}{s}$ $d/t=157/1=157m/s$

Now we can use the general expression for a Centripetal Force:

$F_{c} = m a_{c} = m \frac{v^{2}}{r}$ $F_c=ma_c=mv^2/r$

$F = 2 \cdot \frac{157^{2}}{5} = 9859.6 \approx 9860 N$ $F=2*(157^2)/5=9859.6~~9860N$

An object with a mass of 2kg2 kg is revolving around a point at a distance of 5m5 m. If the object is revolving at a rate of 5Hz5 Hz, what is the centripetal force on the object?