An object with a mass of $2$ $2$ $k g$ $kg$ is revolving around a point at a distance of $7$ $7$ $m$ $m$ . If the object is making revolutions at a frequency of $13$ $13$ $H z$ $Hz$ , what is the centripetal force acting on the object?

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Answer 1 · 2017-06-17T06:01:30

$F = m r ω^{2} = 2 \times 7 \times {(13 \times 2 π)}^{2} = 93405$ $F =mr\omega^2 =2xx7xx(13xx2\pi)^2 =93 405$ $N$ $N$

The centripetal force is given by:

$F = m r ω^{2}$ $F=mr\omega^2$

where $r$ $r$ is the radius, $m$ $m$ is the mass and $ω$ $\omega$ is the rotational frequency in $r a d s^{- 1}$ $rads^-1$ .

To convert a frequency in $H z$ $Hz$ to $r a d s^{- 1}$ $rads^-1$ we multiply by $2 π$ $2\pi$ .

Therefore $F = m r ω^{2} = 2 \times 7 \times {(13 \times 2 π)}^{2} = 93405$ $F =mr\omega^2 =2xx7xx(13xx2\pi)^2 =93 405$ $N$ $N$

An object with a mass of 22 kg kg is revolving around a point at a distance of 77 mm. If the object is making revolutions at a frequency of 1313 Hz Hz, what is the centripetal force acting on the object?