An object with a mass of $2 k g$ $2 kg$ is revolving around a point at a distance of $7 m$ $7 m$ . If the object is making revolutions at a frequency of $1 H z$ $1 Hz$ , what is the centripetal force acting on the object?

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Answer 1 · 2017-07-19T18:38:02

The centripetal force is $= 552.7 N$ $=552.7N$

The centripetal force is

$F = m \frac{v^{2}}{r} = m r ω^{2}$ $F=mv^2/r=mromega^2$

The mass is $= 2 k g$ $=2kg$

The radius is $r = 7 m$ $r=7m$

The angular velocity is $ω = 2 π f = 2 π \cdot 1 = 2 π r a d s^{- 1}$ $omega=2pif=2pi*1=2pirads^-1$

The centripetal force is

$= 2 \cdot 7 \cdot {(2 π)}^{2} = 552.7 N$ $=2*7*(2pi)^2=552.7N$

Answer 2 · 2017-07-19T18:38:13

$F_{c} = 56 π^{2} N$ $F_c=56pi^2N$

We will first find the angular velocity :

$ω=2pif=2pi*1=2pi(rads)/s$

The centripetal force is :

$F_c=mω^2r=2*4pi^2*7=56pi^2N$

An object with a mass of 2 kg2kg2 kg is revolving around a point at a distance of 7 m7m7 m. If the object is making revolutions at a frequency of 1 Hz1Hz1 Hz, what is the centripetal force acting on the object?