An object with a mass of $24 k g$ $24 kg$ is hanging from an axle with a radius of $12 m$ $12 m$ . If the wheel attached to the axle has a radius of $42 m$ $42 m$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2017-04-02T05:44:07

The force is $= 67.2 N$ $=67.2N$

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The load $= (24 g) N$ $=(24g)N$

Radius of axle $r = 12 m$ $r=12m$

Radius of wheel $R = 42 m$ $R=42m$

Taking moments about the center of the axle

$F \cdot 42 = 24 \cdot g \cdot 12$ $F*42=24*g*12$

$F = \frac{24 \cdot g \cdot 12}{42} = 67.2 N$ $F=(24*g*12)/42=67.2N$

An object with a mass of 24kg24 kg is hanging from an axle with a radius of 12m12 m. If the wheel attached to the axle has a radius of 42m42 m, how much force must be applied to the wheel to keep the object from falling?