An object with a mass of $24 k g$ $24 kg$ is hanging from an axle with a radius of $14 m$ $14 m$ . If the wheel attached to the axle has a radius of $42 m$ $42 m$ , how much force must be applied to the wheel to keep the object from falling?

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An object with a mass of $24 k g$ $24 kg$ is hanging from an axle with a radius of $14 m$ $14 m$ . If the wheel attached to the axle has a radius of $42 m$ $42 m$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2017-01-14T19:20:26

$8 g N$ $8g N$

Explanation:

The moments must balance, so $24 \times 14 = F \times 42$ $24 xx 14 = F xx42$ , where $F$ $F$ is the force that must be applied. Hence $F = 24 \times \frac{14}{42} = 8$ $F=24 xx 14/42 = 8$ . Hence $8 g$ $8g$ , that is, the local weight of a mass of $8 k g$ $8kg$ , since one kilogram has a weight of $g$ $g$ Newtons. (Informally, it would require a "weight' of 8kg on the wheel to balance the 'weight' of 24 kg on the axle.)

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An object with a mass of $24 k g$ $24 kg$ is hanging from an axle with a radius of $14 m$ $14 m$ . If the wheel attached to the axle has a radius of $42 m$ $42 m$ , how much force must be applied to the wheel to keep the object from falling?

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Explanation:

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An object with a mass of 24 kg24kg24 kg is hanging from an axle with a radius of 14 m14m14 m. If the wheel attached to the axle has a radius of 42 m42m42 m, how much force must be applied to the wheel to keep the object from falling?

1 Answer

Explanation:

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An object with a mass of $24 k g$ $24 kg$ is hanging from an axle with a radius of $14 m$ $14 m$ . If the wheel attached to the axle has a radius of $42 m$ $42 m$ , how much force must be applied to the wheel to keep the object from falling?