An object with a mass of $24 k g$ $24 kg$ is hanging from an axle with a radius of $16 m$ $16 m$ . If the wheel attached to the axle has a radius of $72 m$ $72 m$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2018-03-09T07:33:21

The force is $F = 52.3 N$ $F=52.3N$

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The load is $L = 24 g N$ $L=24gN$

The radius of the axle is $r = 16 m$ $r=16m$

The radius of the wheel is $R = 72 m$ $R=72m$

The effort is $= F N$ $=FN$

The acceleration due to gravity is $g = 9.8 m s^{- 2}$ $g=9.8ms^-2$

Taking moments about the center of the axle

$F \cdot 72 = 24 g \cdot 16$ $F*72=24g*16$

$F = \frac{24 g \cdot 16}{72} = 52.3 N$ $F=(24g*16)/72=52.3N$

The force is $F = 52.3 N$ $F=52.3N$

An object with a mass of 24kg24 kg is hanging from an axle with a radius of 16m16 m. If the wheel attached to the axle has a radius of 72m72 m, how much force must be applied to the wheel to keep the object from falling?