An object with a mass of $24 k g$ $24 kg$ is hanging from an axle with a radius of $24 m$ $24 m$ . If the wheel attached to the axle has a radius of $24 m$ $24 m$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2017-07-18T05:32:34

The force is $= 235.2 N$ $=235.2N$

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The load $L = (24 g) N$ $L=(24g)N$

Radius of axle $r = 0.24 m$ $r=0.24m$

Radius of wheel $R = 0.24 m$ $R=0.24m$

Taking moments about the center of the axle

$F \cdot R = L \cdot r$ $F*R=L*r$

$F \cdot 0.24 = 24 g \cdot 0.24$ $F*0.24=24g*0.24$

$F = \frac{24 \cdot g \cdot 0.24}{0.24} = 235.2 N$ $F=(24*g*0.24)/0.24=235.2N$

The force is $F = 235.2 N$ $F=235.2N$

An object with a mass of 24 kg24kg24 kg is hanging from an axle with a radius of 24 m24m24 m. If the wheel attached to the axle has a radius of 24 m24m24 m, how much force must be applied to the wheel to keep the object from falling?