An object with a mass of $24 k g$ $24 kg$ is hanging from an axle with a radius of $24 m$ $24 m$ . If the wheel attached to the axle has a radius of $1 m$ $1 m$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2017-07-18T14:24:34

The force is $= 5644.8 N$ $=5644.8N$

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The load $L = (24 g) N$ $L=(24g)N$

Radius of axle $r = 24 m$ $r=24m$

Radius of wheel $R = 1 m$ $R=1m$

Taking moments about the center of the axle

$F \cdot R = L \cdot r$ $F*R=L*r$

$F \cdot 1 = 24 g \cdot 24$ $F*1=24g*24$

$F = \frac{24 \cdot g \cdot 24}{1} = 5644.8 N$ $F=(24*g*24)/1=5644.8N$

The force is $F = 5644.8 N$ $F=5644.8N$

An object with a mass of 24kg24 kg is hanging from an axle with a radius of 24m24 m. If the wheel attached to the axle has a radius of 1m1 m, how much force must be applied to the wheel to keep the object from falling?