An object with a mass of $24 k g$ $24 kg$ is hanging from an axle with a radius of $24 m$ $24 m$ . If the wheel attached to the axle has a radius of $12 m$ $12 m$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2017-07-08T06:20:32

The force is $= 470.4 N$ $=470.4N$

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The load $L = (24 g) N$ $L=(24g)N$

Radius of axle $r = 24 m$ $r=24m$

Radius of wheel $R = 12 m$ $R=12m$

Taking moments about the center of the axle

$F \cdot R = L \cdot r$ $F*R=L*r$

$F \cdot 12 = 24 \cdot g \cdot 24$ $F*12=24*g*24$

$F = \frac{24 \cdot g \cdot 24}{12} = 470.4 N$ $F=(24*g*24)/12=470.4N$

The force is $F = 470.4 N$ $F=470.4N$

An object with a mass of 24kg24 kg is hanging from an axle with a radius of 24m24 m. If the wheel attached to the axle has a radius of 12m12 m, how much force must be applied to the wheel to keep the object from falling?