An object with a mass of $24 k g$ $24 kg$ is hanging from an axle with a radius of $5 m$ $5 m$ . If the wheel attached to the axle has a radius of $12 m$ $12 m$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2017-12-12T09:26:03

The force is $= 98 N$ $=98N$

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The load is $L = 24 g N$ $L=24gN$

The radius of the axle is $r = 5 m$ $r=5m$

The radius of the wheel is $R = 12 m$ $R=12m$

The effort is $= F N$ $=FN$

The acceleration due to gravity is $g = 9.8 m s^{- 2}$ $g=9.8ms^-2$

Taking moments about the center of the axle

$F \cdot 12 = 24 g \cdot 5$ $F*12=24g*5$

$F = \frac{24 g \cdot 5}{12} = N$ $F=(24g*5)/12=N$

The force is $F = 98 N$ $F=98N$

An object with a mass of 24kg24 kg is hanging from an axle with a radius of 5m5 m. If the wheel attached to the axle has a radius of 12m12 m, how much force must be applied to the wheel to keep the object from falling?