An object with a mass of $24 k g$ $24 kg$ is hanging from an axle with a radius of $6 m$ $6 m$ . If the wheel attached to the axle has a radius of $48 m$ $48 m$ , how much force must be applied to the wheel to keep the object from falling?

Question

1227 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-03T08:47:53

The force is $= 29.4 N$ $=29.4N$

enter image source here

The load L=(24g)N#

Radius of axle $r = 6 m$ $r=6m$

Radius of wheel $R = 48 m$ $R=48m$

Taking moments about the center of the axle

$F \cdot R = L \cdot r$ $F*R=L*r$

$F \cdot 48 = 24 \cdot g \cdot 6$ $F*48=24*g*6$

$F = \frac{24 \cdot g \cdot 6}{48} = 29.4 N$ $F=(24*g*6)/48=29.4N$

An object with a mass of 24kg24 kg is hanging from an axle with a radius of 6m6 m. If the wheel attached to the axle has a radius of 48m48 m, how much force must be applied to the wheel to keep the object from falling?