An object with a mass of $25 k g$ $25 kg$ is lying still on a surface and is compressing a horizontal spring by $\frac{5}{3} m$ $5/3 m$ . If the spring's constant is $9 \frac{k g}{s^{2}}$ $9 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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Answer 1 · 2017-05-12T08:12:14

The coefficient of static friction is $= 0.06$ $=0.06$

The coefficient of static friction is

$μ_{s} = \frac{F_{r}}{N}$ $mu_s=F_r/N$

$F_{r} = k \cdot x$ $F_r=k*x$

The spring constant is $k = 9 k g s^{- 2}$ $k=9kgs^-2$

The compression is $x = \frac{5}{3} m$ $x=5/3m$

Therefore,

$F_{r} = 9 \cdot \frac{5}{3} = 15 N$ $F_r=9*5/3=15N$

The normal force is

$N = m g = 25 g N$ $N=mg=25gN$

The coefficient of static friction is

$F_{r} = \frac{15}{25 g} = 0.06$ $F_r=15/(25g)=0.06$

An object with a mass of 25kg 25 kg is lying still on a surface and is compressing a horizontal spring by 53m5/3 m. If the spring's constant is 9kgs2 9 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?