Question

An object with a mass of `3 kg` is hanging from a spring with a constant of `8 (kg)/s^2`. If the spring is stretched by `1 m`, what is the net force on the object?

Answer 1

`22N`

Explanation:

Due to stretching the spring by `1m` , restoring force acting upwards is `F = k x=8×1N` i.e `8 N`

Now,downwards force acting on the mass is its weight i.e `mg=(3×10) N` or `30N`

So,net force acting downwards is `(30-8)N` or, `22N`