An object with a mass of $3 k g$ $3 kg$ is hanging from an axle with a radius of $6 c m$ $6 cm$ . If the wheel attached to the axle has a radius of $16 c m$ $16 cm$ , how much force must be applied to the wheel to keep the object from falling?

Question

1386 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-12T05:56:15

The force is $F = 11.03 N$ $F=11.03N$

www.odicis.org

The load is $L = 3 g N$ $L=3gN$

The radius of the axle is $r = 0.06 m$ $r=0.06m$

The radius of the wheel is $R = 0.16 m$ $R=0.16m$

The effort is $= F N$ $=FN$

The acceleration due to gravity is $g = 9.8 m s^{- 2}$ $g=9.8ms^-2$

Taking moments about the center of the axle

$F \cdot 0.16 = 3 g \cdot 0.06$ $F*0.16=3g*0.06$

$F = \frac{3 g \cdot 0.06}{0.16} = 11.03 N$ $F=(3g*0.06)/0.16=11.03N$

The force is $F = 11.03 N$ $F=11.03N$

An object with a mass of 3 kg3kg3 kg is hanging from an axle with a radius of 6 cm6cm6 cm. If the wheel attached to the axle has a radius of 16 cm16cm16 cm, how much force must be applied to the wheel to keep the object from falling?