An object with a mass of $3 k g$ $3 kg$ is lying on a surface and is compressing a horizontal spring by $25 c m$ $25 cm$ . If the spring's constant is $9 \frac{k g}{s^{2}}$ $9 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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Answer 1 · 2017-07-22T09:51:55

The coefficient of friction is $= 0.077$ $=0.077$

The coefficient of static friction is

$μ_{s} = \frac{F_{r}}{N}$ $mu_s=F_r/N$

$F_{r} = k \cdot x$ $F_r=k*x$

The spring constant is $k = 9 k g s^{- 2}$ $k=9kgs^-2$

The compression is $x = 0.25 m$ $x=0.25m$

Therefore,

$F_{r} = 9 \cdot 0.25 = 2.25 N$ $F_r=9*0.25=2.25N$

The normal force is

$N = m g = 3 g N$ $N=mg=3gN$

The coefficient of static friction is

$μ_{s} = \frac{2.25}{3 g} = 0.077$ $mu_s=(2.25)/(3g)=0.077$

An object with a mass of 3kg 3 kg is lying on a surface and is compressing a horizontal spring by 25cm25 cm. If the spring's constant is 9kgs2 9 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?