An object with a mass of $3 k g$ $3 kg$ is lying on a surface and is compressing a horizontal spring by $30 c m$ $30 cm$ . If the spring's constant is $9 \frac{k g}{s^{2}}$ $9 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

Question

1454 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-09T14:51:31

The coefficient of static friction is $= 0.092$ $=0.092$

The mass is $m = 3 k g$ $m=3kg$

The compression of the spring is $x = 0.30 m$ $x=0.30m$

The spring constant is $k = 9 k g s^{- 2}$ $k=9kgs^-2$

The reaction of the spring is $R = k x = 9 \cdot 0.3 = 2.7 N$ $R=kx=9*0.3=2.7N$

The acceleration due to gravity is $g = 9.8 m s^{- 2}$ $g=9.8ms^-2$

The normal reaction of the object is

$N = m g = 3 \cdot 9.8 = 29.4 N$ $N=mg=3*9.8=29.4N$

The coefficient of static friction is

$μ_{s} = \frac{R}{N} = \frac{2.7}{29.4} = 0.092$ $mu_s=R/N=2.7/29.4=0.092$

An object with a mass of 3kg 3 kg is lying on a surface and is compressing a horizontal spring by 30cm30 cm. If the spring's constant is 9kgs2 9 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?