An object with a mass of $3 k g$ $3 kg$ is lying still on a surface and is compressing a horizontal spring by $60 c m$ $60 c m$ . If the spring's constant is $6 \frac{k g}{s^{2}}$ $6 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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Answer 1 · 2017-07-12T07:21:37

The coefficient of static friction is $= 0.12$ $=0.12$

The coefficient of static friction is

$μ_{s} = \frac{F_{r}}{N}$ $mu_s=F_r/N$

$F_{r} = k \cdot x$ $F_r=k*x$

The spring constant is $k = 6 k g s^{- 2}$ $k=6kgs^-2$

The compression is $x = 0.6 m$ $x=0.6m$

Therefore,

$F_{r} = 6 \cdot 0.6 = 3.6 N$ $F_r=6*0.6=3.6N$

The normal force is

$N = m g = 3 g N$ $N=mg=3gN$

The coefficient of static friction is

$μ_{s} = \frac{3.6}{3 g} = 0.12$ $mu_s=(3.6)/(3g)=0.12$

An object with a mass of 3 kg3kg 3 kg is lying still on a surface and is compressing a horizontal spring by 60 c m60cm60 c m. If the spring's constant is 6 (kg)/s^26kgs2 6 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?