An object with a mass of $3 kg$ is revolving around a point at a distance of $4 m$ . If the object is making revolutions at a frequency of $2 Hz$ , what is the centripetal force acting on the object?

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Answer 1 · 2018-05-26T08:10:20

The centripetal force is $=1895N$

The centripetal force is

$F=mromega^2$

The mass of the object is

$m=3kg$

The radius of the circle is

$r=4m$

The frequency of rotation is

$f=2Hz$

The angular velocity is

$omega=2pif=2*pi*2=4pirads^-1$

Therefore,

the centripetal force is

$F=3*4*(4pi)^2=1895N$

An object with a mass of 3 kg3 kg is revolving around a point at a distance of 4 m4 m. If the object is making revolutions at a frequency of 2 Hz2 Hz, what is the centripetal force acting on the object?