An object with a mass of #4 kg# is hanging from a spring with a constant of #2 (kg)/s^2#. If the spring is stretched by #5 m#, what is the net force on the object?

Question

1384 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-01-02T10:33:35

The net force is #=29.2N "downwards"#

Solving in the downward direction #darr_+#

The acceleration due to gravity is #g=9.8ms^-2#

The weight of the object is #vecw=mg=4*9.8=39.2N#

The spring constant is #k=2kgs^-2#

The extension is #x=5m#

The force due to the extension of the spring is

#vecF=-kx=-2*5=-10N#

The net force is

#F_("net")=vecw+vecF=39.2-10=29.2N#