An object with a mass of $4 k g$ $4 kg$ is lying on a surface and is compressing a horizontal spring by $8 c m$ $8 cm$ . If the spring's constant is $2 \frac{k g}{s^{2}}$ $2 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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An object with a mass of $4 k g$ $4 kg$ is lying on a surface and is compressing a horizontal spring by $8 c m$ $8 cm$ . If the spring's constant is $2 \frac{k g}{s^{2}}$ $2 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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Answer 1 · 2016-02-02T15:08:40

$μ = 2 \times \frac{.08}{4 \times 9.81} = \frac{.04}{9.81} \approx .004$ $mu = 2xx.08/(4xx9.81) = .04/9.81 ~~.004$

Explanation:

Take FBD:
1) y-direction $N = m g$ $N = mg$
2) x-direction $F_{m s} = μ N$ $F_(ms) = muN$
Insert 1) into 2)
$k x = μ m g$ $kx = mumg$
$μ = \frac{k x}{m g}$ $mu = (kx)/(mg)$
$μ = 2 \times \frac{.08}{4 \times 9.81} = \frac{.04}{9.81} \approx .004$ $mu = 2xx.08/(4xx9.81) = .04/9.81 ~~.004$

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An object with a mass of $4 k g$ $4 kg$ is lying on a surface and is compressing a horizontal spring by $8 c m$ $8 cm$ . If the spring's constant is $2 \frac{k g}{s^{2}}$ $2 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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Explanation:

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An object with a mass of 4kg 4 kg is lying on a surface and is compressing a horizontal spring by 8cm8 cm. If the spring's constant is 2kgs2 2 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?

1 Answer

Explanation:

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An object with a mass of $4 k g$ $4 kg$ is lying on a surface and is compressing a horizontal spring by $8 c m$ $8 cm$ . If the spring's constant is $2 \frac{k g}{s^{2}}$ $2 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?