An object with a mass of $4 k g$ $4 kg$ is lying on a surface and is compressing a horizontal spring by $8 c m$ $8 cm$ . If the spring's constant is $6 \frac{k g}{s^{2}}$ $6 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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Answer 1 · 2016-02-19T01:22:23

$\Rightarrow μ = \frac{48}{40} = 1.2$ $=> mu = 48/40 =1.2$

$F = k x$ $F =kx$

k = 6N/m x = 8cm

F = `48N

This F = frictional force = f

$f = μ N = μ m g = μ 10 \cdot 4 = 40 μ$ $f = mu N = mu mg = mu 10 * 4 = 40 mu$

$\Rightarrow μ = \frac{48}{40} = 1.2$ $=> mu = 48/40 =1.2$

An object with a mass of 4kg 4 kg is lying on a surface and is compressing a horizontal spring by 8cm8 cm. If the spring's constant is 6kgs2 6 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?