An object with a mass of 4 kg is pushed along a linear path with a kinetic friction coefficient of u_k(x)= 1+3cscx . How much work would it take to move the object over #x in [(pi)/6, (pi)/4], where x is in meters?

1 Answer
Jan 24, 2018

The work is =61.5J

Explanation:

"Reminder : "

intcscxdx=ln|(tan(x/2))|+C

The work done is

W=F*d

The frictional force is

F_r=mu_k*N

The coefficient of kinetic friction is mu_k=(1+3csc(x))

The normal force is N=mg

The mass of the object is m=4kg

F_r=mu_k*mg

=4*(1+3csc(x))g

The work done is

W=4gint_(1/6pi)^(1/4pi)(1+3csc(x))dx

=4g*[x+3ln|(tan(x/2))|]_(1/6pi)^(1/4pi)

=4g(1/4pi+ln(tan(1/8pi)))-(1/6pi+ln(tan(1/12pi))

=4g(1.57)

=61.5J