An object with a mass of $5 k g$ $5 kg$ is hanging from an axle with a radius of $18 c m$ $18 cm$ . If the wheel attached to the axle has a radius of $42 c m$ $42 cm$ , how much work would it take to turn the wheel $12 c m$ $12 cm$ ?

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Answer 1 · 2017-07-05T16:15:30

The work is $= 2.52 J$ $=2.52J$

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The load $L = (5 g) N$ $L=(5g)N$

Radius of axle $r = 0.18 m$ $r=0.18m$

Radius of wheel $R = 0.42 m$ $R=0.42m$

Taking moments about the center of the axle

$F \cdot R = L \cdot r$ $F*R=L*r$

$F \cdot 0.42 = 5 \cdot g \cdot 0.18$ $F*0.42=5*g*0.18$

$F = \frac{5 \cdot g \cdot 0.18}{0.42} = 21 N$ $F=(5*g*0.18)/0.42=21N$

The force is $F = 21 N$ $F=21N$

The distance is $d = 0.12 m$ $d=0.12m$

The work is

$W = F d = 21 \cdot 0.12 = 2.52 J$ $W=Fd=21*0.12=2.52J$

An object with a mass of 5 kg5kg5 kg is hanging from an axle with a radius of 18 cm18cm18 cm. If the wheel attached to the axle has a radius of 42 cm42cm42 cm, how much work would it take to turn the wheel 12 cm12cm12 cm?