An object with a mass of $5 k g$ $5 kg$ is hanging from an axle with a radius of $24 c m$ $24 cm$ . If the wheel attached to the axle has a radius of $38 c m$ $38 cm$ , how much work would it take to turn the wheel a length equal to the circumference of the axle?

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Answer 1 · 2016-07-02T05:04:46

$\approx 73.85 J$ $~~73.85J$

Given

$The radius of the axle (r) = 24 c m 0.24 m$ $"The radius of the axle " (r) =24cm0.24m$
$The mass of the object (m) = 5 k g$ $"The mass of the object " (m) =5kg$

We are to calculate the work done to lift the object by turning the wheel a length equal to the circumference of the axle.

$Now circumference of the axle (l) = 2 π r = 2 \times π \times 0.24 m$ $"Now circumference of the axle" (l)=2pir=2xxpixx0.24m$

Actually the work done occurs due to the lifting of the object against the gravitational pull by length $l = 2 π r$ $l=2pir$

So $Work done (W) = m \times g \times 2 π r$ $"Work done"(W)=mxxgxx2pir$

$= 5 \times 9.8 \times 2 \times 3.14 \times 0.24 J \approx 73.85 J$ $=5xx9.8xx2xx3.14xx0.24J~~73.85J$

An object with a mass of 5 kg5kg5 kg is hanging from an axle with a radius of 24 cm24cm24 cm. If the wheel attached to the axle has a radius of 38 cm38cm38 cm, how much work would it take to turn the wheel a length equal to the circumference of the axle?