An object with a mass of $5 k g$ $5 kg$ is lying on a surface and is compressing a horizontal spring by $20 c m$ $20 cm$ . If the spring's constant is $9 \frac{k g}{s^{2}}$ $9 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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Answer 1 · 2017-05-12T05:49:34

The coefficient of static friction is $= 0.04$ $=0.04$

The coefficient of static friction is

$μ_{s} = \frac{F_{r}}{N}$ $mu_s=F_r/N$

$F_{r} = k \cdot x$ $F_r=k*x$

The spring constant is $k = 9 k g s^{- 2}$ $k=9kgs^-2$

The compression is $x = 0.2 m$ $x=0.2m$

Therefore,

$F_{r} = 9 \cdot 0.2 = 1.8 N$ $F_r=9*0.2=1.8N$

The normal force is

$N = m g = 5 g N$ $N=mg=5gN$

The coefficient of static friction is

$F_{r} = \frac{1.8}{5 g} = 0.04$ $F_r=1.8/(5g)=0.04$

An object with a mass of 5kg 5 kg is lying on a surface and is compressing a horizontal spring by 20cm20 cm. If the spring's constant is 9kgs2 9 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?