An object with a mass of $5 kg$ is lying still on a surface and is compressing a horizontal spring by $5/2 m$ . If the spring's constant is $4 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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Answer 1 · 2017-05-06T12:29:14

The coefficient of static friction is $=0.05$

The coefficient of static friction is

$mu_s=F_r/N$

$F_r=k*x$

The spring constant is $k=4kgs^-2$

The compression is $x=5/2m$

Therefore,

$F_r=4*5/2=10N$

The normal force is

$N=mg=5gN$

The coefficient of static friction is

$F_r=10/(5g)=0.05$

An object with a mass of 5 kg 5 kg is lying still on a surface and is compressing a horizontal spring by 5/2 m5/2 m. If the spring's constant is 4 (kg)/s^2 4 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?