An object with a mass of #5 kg# is on a surface with a kinetic friction coefficient of # 2 #. How much force is necessary to accelerate the object horizontally at #6 m/s^2#?

↳Redirected from "How do I change #int_0^1int_0^sqrt(1-x^2)int_sqrt(x^2+y^2)^sqrt(2-x^2-y^2)xydzdydx# to cylindrical or spherical coordinates?"
1 Answer
Sunayan S
Jul 6, 2017

#130N#

Explanation:

To equalize the frictional force, we have to give force #mumg=2×5×10=100N#
Next,we have to give force #5×6=30N# force for acceleration.
Hence total force is #100+30=130N#

Related questions
See all questions in Frictional Forces
Impact of this question
1715 views around the world
You can reuse this answer
Creative Commons License