An object with a mass of $5 k g$ $5 kg$ is on a surface with a kinetic friction coefficient of $2$ $2$ . How much force is necessary to accelerate the object horizontally at $6 \frac{m}{s^{2}}$ $6 m/s^2$ ?

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An object with a mass of $5 k g$ $5 kg$ is on a surface with a kinetic friction coefficient of $2$ $2$ . How much force is necessary to accelerate the object horizontally at $6 \frac{m}{s^{2}}$ $6 m/s^2$ ?

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Answer 1 · 2017-07-06T05:41:14

$130 N$ $130N$

Explanation:

To equalize the frictional force, we have to give force $μ m g = 2 \times 5 \times 10 = 100 N$ $mumg=2×5×10=100N$
Next,we have to give force $5 \times 6 = 30 N$ $5×6=30N$ force for acceleration.
Hence total force is $100 + 30 = 130 N$ $100+30=130N$

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An object with a mass of $5 k g$ $5 kg$ is on a surface with a kinetic friction coefficient of $2$ $2$ . How much force is necessary to accelerate the object horizontally at $6 \frac{m}{s^{2}}$ $6 m/s^2$ ?

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An object with a mass of $5 k g$ $5 kg$ is on a surface with a kinetic friction coefficient of $2$ $2$ . How much force is necessary to accelerate the object horizontally at $6 \frac{m}{s^{2}}$ $6 m/s^2$ ?