An object with a mass of $5 kg$ is on a surface with a kinetic friction coefficient of $4$ . How much force is necessary to accelerate the object horizontally at $7 m/s^2$ ?

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Answer 1 · 2017-02-19T03:52:45

231 Newtons

Newton's Law

$F_"net" = ma$

$F_"applied" - F_"friction" = ma$

Friction equation where u is the coefficient of friction

$F_"applied" - uF_"normal" = ma$

The magnitude of normal force is equal to the force of gravity

$F_"applied" - umg = ma$

$F_"applied" = ma + umg$

Plugging in numbers

$= 5*7 + 4*5*9.8$

$=231$ Newtons of force that needs to be applied

An object with a mass of 5 kg5 kg is on a surface with a kinetic friction coefficient of 4 4 . How much force is necessary to accelerate the object horizontally at 7 m/s^2 7 m/s^2?