An object with a mass of $5 k g$ $5 kg$ is on a surface with a kinetic friction coefficient of $4$ $4$ . How much force is necessary to accelerate the object horizontally at $17 \frac{m}{s^{2}}$ $17 m/s^2$ ?

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Answer 1 · 2017-04-09T07:01:51

The force is $= 281 N$ $=281N$

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The frictional force is

$F_{r} = μ_{k} \cdot N$ $F_r=mu_k*N$

The normal force is $N = m g$ $N=mg$

So,

$F_{r} = μ_{k} \cdot m g$ $F_r=mu_k*mg$

Resolving in the horizontal direction $\to^{+}$ $rarr^+$

$F - F_{r} = m a$ $F-F_r=ma$

So,

$F = F_{r} + m a$ $F=F_r+ma$

$F = μ_{k} m g + m a$ $F=mu_kmg+ma$

$= m (μ_{k} g + a)$ $=m(mu_kg+a)$

$= 5 (4 \cdot 9.8 + 17)$ $=5(4*9.8+17)$

$= 5 \cdot 56.2 = 281 N$ $=5*56.2=281N$

An object with a mass of 5kg5 kg is on a surface with a kinetic friction coefficient of 4 4 . How much force is necessary to accelerate the object horizontally at 17ms2 17 m/s^2?