An object with a mass of $5 k g$ $5 kg$ is on a surface with a kinetic friction coefficient of $3$ $3$ . How much force is necessary to accelerate the object horizontally at $2 \frac{m}{s^{2}}$ $2 m/s^2$ ?

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Answer 1 · 2017-02-11T12:05:10

$157 N$ $157N$

law of friction $F = μ \times R$ $" "F=muxxR$

$R = 5 g where g = 9.8 m s^{- 2}$ $R=5g" where "g=9.8ms^(-2)$

we will leave the calculation of $g$ $g$ until the end.

so $F = 3 \times 5 g = 15 g N$ $F=3xx5g=15g ""N$

N2L

$F_{r e s} = m a$ $F_(res)=ma$

Let $P =$ $P=$ the force required

$P - 15 g = 5 \times 2$ $P-15g=5xx2$

$P = 10 + 15 g = 10 + 147 = 157 N$ $P=10+15g=10+147=157N$

An object with a mass of 5kg5 kg is on a surface with a kinetic friction coefficient of 3 3 . How much force is necessary to accelerate the object horizontally at 2ms22 m/s^2?