An object with a mass of $5 k g$ $5 kg$ is on a surface with a kinetic friction coefficient of $4$ $4$ . How much force is necessary to accelerate the object horizontally at $3 \frac{m}{s^{2}}$ $3 m/s^2$ ?

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Answer 1 · 2017-05-28T07:12:38

The force is $= 211 N$ $=211N$

The normal reaction is $N = m g = 5 g$ $N=mg=5g$

The frictional force

$F_{f} = μ_{k} . N$ $F_f=mu_k.N$

$F_{f} = 4 \cdot 5 g = 20 g$ $F_f=4*5g=20g$

Let the force necessary to accelerate the object be $F$ $F$

Then,

$F - F_{f} = m \cdot a$ $F-F_f=m*a$

$F = F_{f} + m \cdot a$ $F=F_f+m*a$

$= 20 g + 5 \cdot 3$ $=20g+5*3$

$= 211 N$ $=211 N$

An object with a mass of 5kg5 kg is on a surface with a kinetic friction coefficient of 4 4 . How much force is necessary to accelerate the object horizontally at 3ms2 3 m/s^2?