An object with a mass of $5 kg$ is pushed along a linear path with a kinetic friction coefficient of $u_k(x)= x^2+2$ . How much work would it take to move the object over #x in [2, 5], where x is in meters?

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An object with a mass of $5 kg$ is pushed along a linear path with a kinetic friction coefficient of $u_k(x)= x^2+2$ . How much work would it take to move the object over #x in [2, 5], where x is in meters?

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Answer 1 · 2016-03-05T05:33:33

$=2250 J$

Explanation:

work done against the frictional force
W $=int_2^5u_k(x)mg*dx$
$=int_2^5(x^2+2)*5*10*dx$ (Given mass m = 5kg and taking g $10ms^-2$ )
$=50int_2^5(x^2+2)dx$
$=50[x^3/3+2x]_2^5$
$=50[(5^3/3+2*5)-(2^3/3+2*2)]$
$=50(117/3+6)$
$=50(135/3)50*45=2250 J$
Here
${kg*ms^-2*m=N*m=J]$

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An object with a mass of $5 kg$ is pushed along a linear path with a kinetic friction coefficient of $u_k(x)= x^2+2$ . How much work would it take to move the object over #x in [2, 5], where x is in meters?

1 Answer

Explanation:

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An object with a mass of 5 kg5 kg is pushed along a linear path with a kinetic friction coefficient of u_k(x)= x^2+2 u_k(x)= x^2+2 . How much work would it take to move the object over #x in [2, 5], where x is in meters?

1 Answer

Explanation:

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An object with a mass of $5 kg$ is pushed along a linear path with a kinetic friction coefficient of $u_k(x)= x^2+2$ . How much work would it take to move the object over #x in [2, 5], where x is in meters?