An object with a mass of $5 k g$ $5 kg$ is revolving around a point at a distance of $3 m$ $3 m$ . If the object is making revolutions at a frequency of $17 H z$ $17 Hz$ , what is the centripetal force acting on the object?

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Answer 1 · 2016-01-18T18:07:34

$1.712 \times 10^{5} N$ $1.712xx10^5"N"$

The time period $T$ $T$ for 1 revolution $= \frac{1}{f} = \frac{1}{17} s$ $=1/f=1/17s$

$v = \frac{d}{T} = \frac{2 π r}{T} = \frac{2 π 3}{\frac{1}{17}} = 320.84 m/s$ $v=d/T=(2pir)/T=(2pi3)/(1/17)=320.84"m/s"$

The centripetal force is given by:

$F = \frac{m v^{2}}{r} = \frac{5 \times {320.84}^{2}}{3} = 1.712 \times 10^{5} N$ $F=(mv^2)/r=(5xx320.84^2)/3=1.712xx10^5"N"$

An object with a mass of 5 kg5kg5 kg is revolving around a point at a distance of 3 m3m3 m. If the object is making revolutions at a frequency of 17 Hz17Hz17 Hz, what is the centripetal force acting on the object?