An object with a mass of $5$ $kg$ is revolving around a point at a distance of $3$ $m$ . If the object is making revolutions at a frequency of $13$ $Hz$ , what is the centripetal force acting on the object?

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Answer 1 · 2016-02-14T22:16:35

The centripetal force is given by $F=momega^2r$ where $m$ is the mass $(kg)$ , $omega$ is the frequency $(rads^-1)$ and $r$ is the radius $(m)$ .

$F=momega^2r=5*94.25^2*3=133246$ $N$

We need to convert the frequency: $15$ $Hz=30pi=94.25$ rads^-1#.

An object with a mass of 55 kgkg is revolving around a point at a distance of 33 mm. If the object is making revolutions at a frequency of 1313 HzHz, what is the centripetal force acting on the object?