An object with a mass of #6 kg# is hanging from a spring with a constant of #2 (kg)/s^2#. If the spring is stretched by #9 m#, what is the net force on the object?

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Answer 1 · 2017-03-12T10:45:52

The net force is #=40.8N# acting downwards.

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Let's resolve in the vertical direction #uarr^+#

#F_1=kx=9*2=18N#

#F_2=-6g=-6g=-58.8N#

The net force is

#F=F_1+F_2=18-58.8=-40.8N#

The force is acting downwards.