An object with a mass of #6 kg# is hanging from a spring with a constant of #4 (kg)/s^2#. If the spring is stretched by #12 m#, what is the net force on the object?

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Answer 1 · 2017-07-29T09:25:12

The net force on the object is #=10.8N# acting downwards

Resolving in the direction #darr_+#

The weight is #=(mg)N#

The force in the spring is #=(kDeltax) N#

The spring constant is #k=4kgs^-2#

The elongation is #Deltax=12m#

The mass is #m=6kg#

The net force is

#=mg-kDeltax#

#=6g-4*12#

#=10.8N#