An object with a mass of $6 k g$ $6 kg$ is hanging from an axle with a radius of $7 m$ $7 m$ . If the wheel attached to the axle has a radius of $48 m$ $48 m$ , how much force must be applied to the wheel to keep the object from falling?

Question

1298 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-30T07:06:15

The force is $= 8.575 N$ $=8.575N$

enter image source here

The load is $L = 6 g N$ $L=6gN$

The radius of the axle is $r = 7 m$ $r=7m$

The radius of the wheel is $R = 48 m$ $R=48m$

The effort is $= F N$ $=FN$

The acceleration due to gravity is $g = 9.8 m s^{- 2}$ $g=9.8ms^-2$

Taking moments about the center of the axle

$F \cdot 48 = 6 g \cdot 7$ $F*48=6g*7$

$F = \frac{6 g \cdot 7}{48} = 8.575 N$ $F=(6g*7)/48=8.575N$

The force is $F = 8.575 N$ $F=8.575N$

An object with a mass of 6kg6 kg is hanging from an axle with a radius of 7m7 m. If the wheel attached to the axle has a radius of 48m48 m, how much force must be applied to the wheel to keep the object from falling?