An object with a mass of $6 k g$ $6 kg$ is lying still on a surface and is compressing a horizontal spring by $\frac{3}{4} m$ $3/4 m$ . If the spring's constant is $8 \frac{k g}{s^{2}}$ $8 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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An object with a mass of $6 k g$ $6 kg$ is lying still on a surface and is compressing a horizontal spring by $\frac{3}{4} m$ $3/4 m$ . If the spring's constant is $8 \frac{k g}{s^{2}}$ $8 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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Answer 1 · 2018-06-25T01:57:33

coefficient of static friction( $μ$ $mu$ ) $= 0.0375$ $=0.0375$

Explanation:

At equilibrium, force exerted by spring on object is balanced by force of friction.
So,
$\frac{1}{2} k x^{2} = μ m g$ $1/2kx^2=mumg$

substituting $k = 8 k g s^{- 2}, x = \frac{3}{4} m, m = 6 k g and g = 10 m s^{- 2}$ $k=8kgs^(-2) , x=3/4m , m=6kg and g=10ms^(-2)$ , we get $μ = 0.0375$ $mu = 0.0375$

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An object with a mass of $6 k g$ $6 kg$ is lying still on a surface and is compressing a horizontal spring by $\frac{3}{4} m$ $3/4 m$ . If the spring's constant is $8 \frac{k g}{s^{2}}$ $8 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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Explanation:

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An object with a mass of 6kg 6 kg is lying still on a surface and is compressing a horizontal spring by 34m3/4 m. If the spring's constant is 8kgs2 8 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?

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Explanation:

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An object with a mass of $6 k g$ $6 kg$ is lying still on a surface and is compressing a horizontal spring by $\frac{3}{4} m$ $3/4 m$ . If the spring's constant is $8 \frac{k g}{s^{2}}$ $8 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?