An object with a mass of 6kg is pushed along a linear path with a kinetic friction coefficient of uk(x)=1+cotx. How much work would it take to move the object over #x in [(3pi)/4, (7pi)/8], where x is in meters?

1 Answer
Jun 29, 2017

The work is =12.8J

Explanation:

We need

cotxdx=ln|sin(x)|+C

The work done is

W=Fd

The frictional force is

Fr=μkN

The normal force is N=mg

The mass is m=6kg

Fr=μkmg

=6(1+cotx)g

The work done is

W=6g78π34π(1+cotx)dx

=6g[x+lnsin(x)]78π34π

=6g((78π+lnsin(78π))(34π+lnsin(34π)))

=6g(18π0.96+0.35)

=6g(0.217)

=12.8J