An object with a mass of 6kg is pushed along a linear path with a kinetic friction coefficient of uk(x)=1+cotx. How much work would it take to move the object over #x in [(pi)/4, (7pi)/8], where x is in meters?

1 Answer
Jul 21, 2017

The work is =79.4J

Explanation:

We need

cotxdx=ln|sin(x)|+C

The work done is

W=Fd

The frictional force is

Fr=μkN

The normal force is N=mg

The mass is m=6kg

Fr=μkmg

=6(1+cotx)gN

The work done is

W=6g78π14π(1+cotx)dx

=6g[x+ln|sin(x)|]78π14π

=6g((78π+lnsin(78π)))(14π+lnsin(14π)))

=6g(58π0.614)

=6g(1.35)

=79.4J