An object with a mass of 6kg is pushed along a linear path with a kinetic friction coefficient of uk(x)=1+3cscx. How much work would it take to move the object over #x in [(pi)/6, (pi)/4], where x is in meters?

1 Answer
Apr 1, 2016

w=π4π6μk(x)mgdx
w=mgπ4π6(1+3cscx)dx
w=mgπ4π6dx+3mgπ4π6cscxdx

=mgπ4π6dx+3mgπ4π6cscxdx

#= mg(pi/4-pi/6)-3mgln(csc(pi/4)+cot(pi/4)-ln(csc(pi/6)+cot(pi/6)))#
pl put m=6kg
g=9.8ms2
and values from trigonometrical table and calculate
w=6×9.8π123×6×9.8×ln(2+12+3)J