An object with a mass of $6 k g$ $6 kg$ is revolving around a point at a distance of $2 m$ $2 m$ . If the object is making revolutions at a frequency of $9 H z$ $9 Hz$ , what is the centripetal force acting on the object?

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An object with a mass of $6 k g$ $6 kg$ is revolving around a point at a distance of $2 m$ $2 m$ . If the object is making revolutions at a frequency of $9 H z$ $9 Hz$ , what is the centripetal force acting on the object?

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Answer 1 · 2015-12-30T21:46:21

I found $\approx 38 k N$ $~~38kN$

Explanation:

We have that centripetal force is:
$F_{c} = m a_{c} = m \frac{v^{2}}{r}$ $F_c=ma_c=mv^2/r$
Where:
$v = \frac{distance}{time} = \frac{circumference}{period} = \frac{2 π r}{T}$ $v=("distance")/("time")=("circumference")/("period")=(2pir)/T$
With: $T = \frac{1}{frequency} = \frac{1}{9}$ $T=1/("frequency")=1/9$
So:
$v = 2 \cdot 3.14 \cdot 2 \cdot 9 = 113.04 \frac{m}{s}$ $v=2*3.14*2*9=113.04m/s$
So:
$F_{c} = 6 \cdot \frac{{(113.04)}^{2}}{2} = 38, 334 N$ $F_c=6*(113.04)^2/2=38,334N$

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An object with a mass of $6 k g$ $6 kg$ is revolving around a point at a distance of $2 m$ $2 m$ . If the object is making revolutions at a frequency of $9 H z$ $9 Hz$ , what is the centripetal force acting on the object?

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Explanation:

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An object with a mass of 6kg6 kg is revolving around a point at a distance of 2m2 m. If the object is making revolutions at a frequency of 9Hz9 Hz, what is the centripetal force acting on the object?

1 Answer

Explanation:

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An object with a mass of $6 k g$ $6 kg$ is revolving around a point at a distance of $2 m$ $2 m$ . If the object is making revolutions at a frequency of $9 H z$ $9 Hz$ , what is the centripetal force acting on the object?