An object with a mass of 6 kg is revolving around a point at a distance of 2 m. If the object is making revolutions at a frequency of 12 Hz, what is the centripetal force acting on the object?

1 Answer
Jun 8, 2017

The centripetal force is =68219N

Explanation:

The cetripetal force is

F=(mv^2)/r=mromega^2

The mass is m=6kg

The radius is r=2m

The frequency is f=12Hz

The angular velocity is omega=2pif=2pi*12=24pirads^-1

So,

F=6*2*(24pi)^2=68219N